Base | Representation |
---|---|
bin | 1010000110010110000111… |
… | …1111001001100001101011 |
3 | 1110022112201012220111220201 |
4 | 2201211201333021201223 |
5 | 2423412231401413303 |
6 | 35341100253133031 |
7 | 2224150542051361 |
oct | 241454177114153 |
9 | 43275635814821 |
10 | 11104134404203 |
11 | 35a1267429095 |
12 | 12b408018a177 |
13 | 6271666534c9 |
14 | 2a562b735631 |
15 | 143c9d86781d |
hex | a1961fc986b |
11104134404203 has 16 divisors (see below), whose sum is σ = 11756087965440. Its totient is φ = 10458962546400.
The previous prime is 11104134404183. The next prime is 11104134404219. The reversal of 11104134404203 is 30240443140111.
11104134404203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11104134404203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11104134404263) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13377168 + ... + 14182978.
It is an arithmetic number, because the mean of its divisors is an integer number (734755497840).
Almost surely, 211104134404203 is an apocalyptic number.
11104134404203 is a deficient number, since it is larger than the sum of its proper divisors (651953561237).
11104134404203 is a wasteful number, since it uses less digits than its factorization.
11104134404203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 810018.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 11104134404203 its reverse (30240443140111), we get a palindrome (41344577544314).
The spelling of 11104134404203 in words is "eleven trillion, one hundred four billion, one hundred thirty-four million, four hundred four thousand, two hundred three".
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