11104401331 has 4 divisors (see below), whose sum is σ = 11104911432. Its totient is φ = 11103891232.

The previous prime is 11104401323. The next prime is 11104401361. The reversal of 11104401331 is 13310440111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13310440111 = 26959 ⋅493729.

It is a cyclic number.

It is not a de Polignac number, because 11104401331 - 2³ = 11104401323 is a prime.

It is a super-2 number, since 2×11104401331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11104401299 and 11104401308.

It is not an unprimeable number, because it can be changed into a prime (11104401361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220870 + ... + 266443.

It is an arithmetic number, because the mean of its divisors is an integer number (2776227858).

Almost surely, 2^11104401331 is an apocalyptic number.

11104401331 is a deficient number, since it is larger than the sum of its proper divisors (510101).

11104401331 is an equidigital number, since it uses as much as digits as its factorization.

11104401331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 510100.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11104401331 its reverse (13310440111), we get a palindrome (24414841442).

The spelling of 11104401331 in words is "eleven billion, one hundred four million, four hundred one thousand, three hundred thirty-one".