11104405033 has 4 divisors (see below), whose sum is σ = 11121256080. Its totient is φ = 11087553988.

The previous prime is 11104405019. The next prime is 11104405043. The reversal of 11104405033 is 33050440111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11104405033 - 2²⁹ = 10567534121 is a prime.

It is a super-2 number, since 2×11104405033² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11104404995 and 11104405013.

It is not an unprimeable number, because it can be changed into a prime (11104405043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8424535 + ... + 8425852.

It is an arithmetic number, because the mean of its divisors is an integer number (2780314020).

Almost surely, 2^11104405033 is an apocalyptic number.

It is an amenable number.

11104405033 is a deficient number, since it is larger than the sum of its proper divisors (16851047).

11104405033 is an equidigital number, since it uses as much as digits as its factorization.

11104405033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16851046.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 11104405033 its reverse (33050440111), we get a palindrome (44154845144).

The spelling of 11104405033 in words is "eleven billion, one hundred four million, four hundred five thousand, thirty-three".