1110444000131 has 4 divisors (see below), whose sum is σ = 1110502528200. Its totient is φ = 1110385472064.

The previous prime is 1110444000097. The next prime is 1110444000181. The reversal of 1110444000131 is 1310004440111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1110444000131 - 2¹⁸ = 1110443737987 is a prime.

It is a super-2 number, since 2×1110444000131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1110444000181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29235566 + ... + 29273523.

It is an arithmetic number, because the mean of its divisors is an integer number (277625632050).

Almost surely, 2^{1110444000131} is an apocalyptic number.

1110444000131 is a deficient number, since it is larger than the sum of its proper divisors (58528069).

1110444000131 is an equidigital number, since it uses as much as digits as its factorization.

1110444000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58528068.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1110444000131 its reverse (1310004440111), we get a palindrome (2420448440242).

The spelling of 1110444000131 in words is "one trillion, one hundred ten billion, four hundred forty-four million, one hundred thirty-one", and thus it is an aban number.