Base | Representation |
---|---|
bin | 1010000110101100000011… |
… | …1010100110000010111001 |
3 | 1110100002220112111000222222 |
4 | 2201223000322212002321 |
5 | 2424011311113404423 |
6 | 35343512413053425 |
7 | 2224446462646052 |
oct | 241530072460271 |
9 | 43302815430888 |
10 | 11110022013113 |
11 | 35a3808874881 |
12 | 12b5243a87275 |
13 | 62789435a76a |
14 | 2a5a29649729 |
15 | 143ee569e3c8 |
hex | a1ac0ea60b9 |
11110022013113 has 8 divisors (see below), whose sum is σ = 11134681113600. Its totient is φ = 11085382859328.
The previous prime is 11110022013043. The next prime is 11110022013127. The reversal of 11110022013113 is 31131022001111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11110022013113 - 212 = 11110022009017 is a prime.
It is a super-3 number, since 3×111100220131133 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11110022013091 and 11110022013100.
It is not an unprimeable number, because it can be changed into a prime (11110022013913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3871193 + ... + 6099686.
It is an arithmetic number, because the mean of its divisors is an integer number (1391835139200).
Almost surely, 211110022013113 is an apocalyptic number.
It is an amenable number.
11110022013113 is a deficient number, since it is larger than the sum of its proper divisors (24659100487).
11110022013113 is an equidigital number, since it uses as much as digits as its factorization.
11110022013113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9973351.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 11110022013113 its reverse (31131022001111), we get a palindrome (42241044014224).
The spelling of 11110022013113 in words is "eleven trillion, one hundred ten billion, twenty-two million, thirteen thousand, one hundred thirteen".
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