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1111021302105 = 3351113223918523
BaseRepresentation
bin10000001010101110000…
…001111011000101011001
310221012201222120220222000
4100022232001323011121
5121200332423131410
62210221322151213
7143161100151441
oct20125601730531
93835658526860
101111021302105
113991aa619430
1215b3a6952509
13809cc250900
143bab9121121
151dd7834bdc0
hex102ae07b159

1111021302105 has 192 divisors, whose sum is σ = 2343093350400. Its totient is φ = 495133067520.

The previous prime is 1111021302101. The next prime is 1111021302119. The reversal of 1111021302105 is 5012031201111.

It is not a de Polignac number, because 1111021302105 - 22 = 1111021302101 is a prime.

It is a super-3 number, since 3×11110213021053 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1111021302101) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 59971374 + ... + 59989896.

It is an arithmetic number, because the mean of its divisors is an integer number (12203611200).

Almost surely, 21111021302105 is an apocalyptic number.

1111021302105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1111021302105 is an abundant number, since it is smaller than the sum of its proper divisors (1232072048295).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111021302105 is a wasteful number, since it uses less digits than its factorization.

1111021302105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18813 (or 18794 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 18.

Adding to 1111021302105 its reverse (5012031201111), we get a palindrome (6123052503216).

The spelling of 1111021302105 in words is "one trillion, one hundred eleven billion, twenty-one million, three hundred two thousand, one hundred five".