11111003123113 has 4 divisors (see below), whose sum is σ = 11190938397520. Its totient is φ = 11031067848708.

The previous prime is 11111003123071. The next prime is 11111003123123. The reversal of 11111003123113 is 31132130011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111003123113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11111003123123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39967636995 + ... + 39967637272.

It is an arithmetic number, because the mean of its divisors is an integer number (2797734599380).

Almost surely, 2^{11111003123113} is an apocalyptic number.

It is an amenable number.

11111003123113 is a deficient number, since it is larger than the sum of its proper divisors (79935274407).

11111003123113 is an equidigital number, since it uses as much as digits as its factorization.

11111003123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79935274406.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 11111003123113 its reverse (31132130011111), we get a palindrome (42243133134224).

The spelling of 11111003123113 in words is "eleven trillion, one hundred eleven billion, three million, one hundred twenty-three thousand, one hundred thirteen".