Base | Representation |
---|---|
bin | 10000001010110101010… |
… | …110110111010100110011 |
3 | 10221020001112220102102002 |
4 | 100022311112313110303 |
5 | 121201110410412433 |
6 | 2210241433044215 |
7 | 143164122065363 |
oct | 20126526672463 |
9 | 3836045812362 |
10 | 1111144232243 |
11 | 399262a51691 |
12 | 15b41bb5666b |
13 | 80a1b862436 |
14 | 3bacb5a09a3 |
15 | 1dd840309e8 |
hex | 102b55b7533 |
1111144232243 has 4 divisors (see below), whose sum is σ = 1111146344400. Its totient is φ = 1111142120088.
The previous prime is 1111144232213. The next prime is 1111144232279. The reversal of 1111144232243 is 3422324411111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1111144232243 - 212 = 1111144228147 is a prime.
It is a super-2 number, since 2×11111442322432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1111144232203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431333 + ... + 1551881.
It is an arithmetic number, because the mean of its divisors is an integer number (277786586100).
Almost surely, 21111144232243 is an apocalyptic number.
1111144232243 is a deficient number, since it is larger than the sum of its proper divisors (2112157).
1111144232243 is an equidigital number, since it uses as much as digits as its factorization.
1111144232243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2112156.
The product of its digits is 4608, while the sum is 29.
Adding to 1111144232243 its reverse (3422324411111), we get a palindrome (4533468643354).
The spelling of 1111144232243 in words is "one trillion, one hundred eleven billion, one hundred forty-four million, two hundred thirty-two thousand, two hundred forty-three".
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