Base | Representation |
---|---|
bin | 10100101100101010… |
… | …00010101100001011 |
3 | 1001200102020202200002 |
4 | 22112111002230023 |
5 | 140224140024120 |
6 | 5034345233215 |
7 | 542236502525 |
oct | 122625025413 |
9 | 31612222602 |
10 | 11112033035 |
11 | 47924a8984 |
12 | 21a149280b |
13 | 10811c219c |
14 | 775b14a15 |
15 | 45081e375 |
hex | 296542b0b |
11112033035 has 4 divisors (see below), whose sum is σ = 13334439648. Its totient is φ = 8889626424.
The previous prime is 11112033019. The next prime is 11112033043. The reversal of 11112033035 is 53033021111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53033021111 = 7 ⋅7576145873.
It is a cyclic number.
It is not a de Polignac number, because 11112033035 - 24 = 11112033019 is a prime.
It is a super-2 number, since 2×111120330352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11112032998 and 11112033016.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1111203299 + ... + 1111203308.
It is an arithmetic number, because the mean of its divisors is an integer number (3333609912).
Almost surely, 211112033035 is an apocalyptic number.
11112033035 is a deficient number, since it is larger than the sum of its proper divisors (2222406613).
11112033035 is an equidigital number, since it uses as much as digits as its factorization.
11112033035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2222406612.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 11112033035 its reverse (53033021111), we get a palindrome (64145054146).
The spelling of 11112033035 in words is "eleven billion, one hundred twelve million, thirty-three thousand, thirty-five".
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