Base | Representation |
---|---|
bin | 1010000110110100101000… |
… | …1101001001000001010011 |
3 | 1110100022212001121212002020 |
4 | 2201231022031021001103 |
5 | 2424031020242303210 |
6 | 35344533133422523 |
7 | 2224560532012236 |
oct | 241551215110123 |
9 | 43308761555066 |
10 | 11112325353555 |
11 | 35a478aa67618 |
12 | 12b578733aa43 |
13 | 627b706021ba |
14 | 2a5ba750741d |
15 | 1440cc9d0770 |
hex | a1b4a349053 |
11112325353555 has 16 divisors (see below), whose sum is σ = 17808443877120. Its totient is φ = 5916999084768.
The previous prime is 11112325353553. The next prime is 11112325353581. The reversal of 11112325353555 is 55535352321111.
It is not a de Polignac number, because 11112325353555 - 21 = 11112325353553 is a prime.
It is a super-2 number, since 2×111123253535552 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11112325353553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 598392727 + ... + 598411296.
It is an arithmetic number, because the mean of its divisors is an integer number (1113027742320).
Almost surely, 211112325353555 is an apocalyptic number.
11112325353555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11112325353555 is a deficient number, since it is larger than the sum of its proper divisors (6696118523565).
11112325353555 is a wasteful number, since it uses less digits than its factorization.
11112325353555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1196804650.
The product of its digits is 337500, while the sum is 42.
Adding to 11112325353555 its reverse (55535352321111), we get a palindrome (66647677674666).
The spelling of 11112325353555 in words is "eleven trillion, one hundred twelve billion, three hundred twenty-five million, three hundred fifty-three thousand, five hundred fifty-five".
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