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11113003201 = 107103859843
BaseRepresentation
bin10100101100110001…
…01111100011000001
31001200111002001111011
422112120233203001
5140224412100301
65034422120521
7542250653146
oct122630574301
931614061434
1011113003201
114793000873
1221a1880141
131081471951
14775cc83cd
15450961a51
hex29662f8c1

11113003201 has 4 divisors (see below), whose sum is σ = 11216863152. Its totient is φ = 11009143252.

The previous prime is 11113003199. The next prime is 11113003211. The reversal of 11113003201 is 10230031111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10230031111 = 77933131267.

It is a cyclic number.

It is not a de Polignac number, because 11113003201 - 21 = 11113003199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11113003211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51929815 + ... + 51930028.

It is an arithmetic number, because the mean of its divisors is an integer number (2804215788).

Almost surely, 211113003201 is an apocalyptic number.

It is an amenable number.

11113003201 is a deficient number, since it is larger than the sum of its proper divisors (103859951).

11113003201 is a wasteful number, since it uses less digits than its factorization.

11113003201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103859950.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11113003201 its reverse (10230031111), we get a palindrome (21343034312).

The spelling of 11113003201 in words is "eleven billion, one hundred thirteen million, three thousand, two hundred one".

Divisors: 1 107 103859843 11113003201