111131130121 has 4 divisors (see below), whose sum is σ = 121233960144. Its totient is φ = 101028300100.

The previous prime is 111131130113. The next prime is 111131130127. The reversal of 111131130121 is 121031131111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111131130121 - 2³ = 111131130113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111131130095 and 111131130104.

It is not an unprimeable number, because it can be changed into a prime (111131130127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5051414995 + ... + 5051415016.

It is an arithmetic number, because the mean of its divisors is an integer number (30308490036).

Almost surely, 2^111131130121 is an apocalyptic number.

111131130121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

111131130121 is a deficient number, since it is larger than the sum of its proper divisors (10102830023).

111131130121 is a wasteful number, since it uses less digits than its factorization.

111131130121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10102830022.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 111131130121 its reverse (121031131111), we get a palindrome (232162261232).

The spelling of 111131130121 in words is "one hundred eleven billion, one hundred thirty-one million, one hundred thirty thousand, one hundred twenty-one".