Base | Representation |
---|---|
bin | 11001010001001011110111… |
… | …001100101101001110000011 |
3 | 112120111010110021222120021102 |
4 | 121101023313030231032003 |
5 | 104031242101031320003 |
6 | 1032205221330445015 |
7 | 32260013544332030 |
oct | 3121136714551603 |
9 | 476433407876242 |
10 | 111132131120003 |
11 | 32456965899214 |
12 | 1056a199a3376b |
13 | 4a0193ab07376 |
14 | 1d62b768c0387 |
15 | ccac05e50588 |
hex | 6512f732d383 |
111132131120003 has 4 divisors (see below), whose sum is σ = 127008149851440. Its totient is φ = 95256112388568.
The previous prime is 111132131119991. The next prime is 111132131120009. The reversal of 111132131120003 is 300021131231111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111132131120003 - 28 = 111132131119747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111132131120009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7938009365708 + ... + 7938009365721.
It is an arithmetic number, because the mean of its divisors is an integer number (31752037462860).
Almost surely, 2111132131120003 is an apocalyptic number.
111132131120003 is a deficient number, since it is larger than the sum of its proper divisors (15876018731437).
111132131120003 is an equidigital number, since it uses as much as digits as its factorization.
111132131120003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15876018731436.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 111132131120003 its reverse (300021131231111), we get a palindrome (411153262351114).
The spelling of 111132131120003 in words is "one hundred eleven trillion, one hundred thirty-two billion, one hundred thirty-one million, one hundred twenty thousand, three".
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