Base | Representation |
---|---|
bin | 110011110000000000… |
… | …0000101001101010001 |
3 | 101121212000000210010022 |
4 | 1213200000011031101 |
5 | 3310044332100423 |
6 | 123015314513225 |
7 | 11012650651652 |
oct | 1474000051521 |
9 | 347760023108 |
10 | 111132300113 |
11 | 43149316a2a |
12 | 19655b95815 |
13 | a630c79783 |
14 | 554372d529 |
15 | 2d5670ddc8 |
hex | 19e0005351 |
111132300113 has 16 divisors (see below), whose sum is σ = 119162769600. Its totient is φ = 103325932800.
The previous prime is 111132300109. The next prime is 111132300121. The reversal of 111132300113 is 311003231111.
It is a cyclic number.
It is not a de Polignac number, because 111132300113 - 22 = 111132300109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111132300091 and 111132300100.
It is not an unprimeable number, because it can be changed into a prime (111132300133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 591245 + ... + 756197.
It is an arithmetic number, because the mean of its divisors is an integer number (7447673100).
Almost surely, 2111132300113 is an apocalyptic number.
It is an amenable number.
111132300113 is a deficient number, since it is larger than the sum of its proper divisors (8030469487).
111132300113 is a wasteful number, since it uses less digits than its factorization.
111132300113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165632.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 111132300113 its reverse (311003231111), we get a palindrome (422135531224).
The spelling of 111132300113 in words is "one hundred eleven billion, one hundred thirty-two million, three hundred thousand, one hundred thirteen".
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