1111331120131 has 4 divisors (see below), whose sum is σ = 1111334473264. Its totient is φ = 1111327767000.

The previous prime is 1111331119979. The next prime is 1111331120147. The reversal of 1111331120131 is 1310211331111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1111331120131 - 2²³ = 1111322731523 is a prime.

It is a super-2 number, since 2×1111331120131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111331120099 and 1111331120108.

It is not an unprimeable number, because it can be changed into a prime (1111331150131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117215 + ... + 1863016.

It is an arithmetic number, because the mean of its divisors is an integer number (277833618316).

Almost surely, 2^{1111331120131} is an apocalyptic number.

1111331120131 is a deficient number, since it is larger than the sum of its proper divisors (3353133).

1111331120131 is an equidigital number, since it uses as much as digits as its factorization.

1111331120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3353132.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1111331120131 its reverse (1310211331111), we get a palindrome (2421542451242).

The spelling of 1111331120131 in words is "one trillion, one hundred eleven billion, three hundred thirty-one million, one hundred twenty thousand, one hundred thirty-one".