111134113 has 4 divisors (see below), whose sum is σ = 111155200. Its totient is φ = 111113028.

The previous prime is 111134077. The next prime is 111134123. The reversal of 111134113 is 311431111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311431111 = 983 ⋅316817.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111134113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111134123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5056 + ... + 15742.

It is an arithmetic number, because the mean of its divisors is an integer number (27788800).

Almost surely, 2^111134113 is an apocalyptic number.

It is an amenable number.

111134113 is a deficient number, since it is larger than the sum of its proper divisors (21087).

111134113 is a wasteful number, since it uses less digits than its factorization.

111134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21086.

The product of its digits is 36, while the sum is 16.

The square root of 111134113 is about 10542.0165528233. The cubic root of 111134113 is about 480.7830289445.

Adding to 111134113 its reverse (311431111), we get a palindrome (422565224).

The spelling of 111134113 in words is "one hundred eleven million, one hundred thirty-four thousand, one hundred thirteen".