Base | Representation |
---|---|
bin | 110011110000010100… |
… | …1101111001110100011 |
3 | 101121212202120120120102 |
4 | 1213200221233032203 |
5 | 3310110131021011 |
6 | 123020344533015 |
7 | 11013142532516 |
oct | 1474051571643 |
9 | 347782516512 |
10 | 111143220131 |
11 | 431544a5339 |
12 | 1965978116b |
13 | a633301018 |
14 | 5544d72d7d |
15 | 2d5766973b |
hex | 19e0a6f3a3 |
111143220131 has 4 divisors (see below), whose sum is σ = 111505250472. Its totient is φ = 110781189792.
The previous prime is 111143220073. The next prime is 111143220233. The reversal of 111143220131 is 131022341111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111143220131 - 218 = 111142957987 is a prime.
It is a super-2 number, since 2×1111432201312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111143220031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181014710 + ... + 181015323.
It is an arithmetic number, because the mean of its divisors is an integer number (27876312618).
Almost surely, 2111143220131 is an apocalyptic number.
111143220131 is a deficient number, since it is larger than the sum of its proper divisors (362030341).
111143220131 is an equidigital number, since it uses as much as digits as its factorization.
111143220131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 362030340.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 111143220131 its reverse (131022341111), we get a palindrome (242165561242).
The spelling of 111143220131 in words is "one hundred eleven billion, one hundred forty-three million, two hundred twenty thousand, one hundred thirty-one".
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