1111434113 has 4 divisors (see below), whose sum is σ = 1113043248. Its totient is φ = 1109824980.

The previous prime is 1111434067. The next prime is 1111434119. The reversal of 1111434113 is 3114341111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1111434113 - 2³⁰ = 37692289 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1111434119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803531 + ... + 804912.

It is an arithmetic number, because the mean of its divisors is an integer number (278260812).

Almost surely, 2^1111434113 is an apocalyptic number.

It is an amenable number.

1111434113 is a deficient number, since it is larger than the sum of its proper divisors (1609135).

1111434113 is an equidigital number, since it uses as much as digits as its factorization.

1111434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1609134.

The product of its digits is 144, while the sum is 20.

The square root of 1111434113 is about 33338.1780096033. The cubic root of 1111434113 is about 1035.8445231244.

Adding to 1111434113 its reverse (3114341111), we get a palindrome (4225775224).

The spelling of 1111434113 in words is "one billion, one hundred eleven million, four hundred thirty-four thousand, one hundred thirteen".