11114352000035 has 4 divisors (see below), whose sum is σ = 13337222400048. Its totient is φ = 8891481600024.

The previous prime is 11114351999987. The next prime is 11114352000071. The reversal of 11114352000035 is 53000025341111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11114352000035 - 2¹⁰ = 11114351999011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11114351999968 and 11114352000013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1111435199999 + ... + 1111435200008.

It is an arithmetic number, because the mean of its divisors is an integer number (3334305600012).

Almost surely, 2^{11114352000035} is an apocalyptic number.

11114352000035 is a deficient number, since it is larger than the sum of its proper divisors (2222870400013).

11114352000035 is an equidigital number, since it uses as much as digits as its factorization.

11114352000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2222870400012.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 11114352000035 its reverse (53000025341111), we get a palindrome (64114377341146).

The spelling of 11114352000035 in words is "eleven trillion, one hundred fourteen billion, three hundred fifty-two million, thirty-five", and thus it is an aban number.