11120110033 has 4 divisors (see below), whose sum is σ = 11133822448. Its totient is φ = 11106397620.

The previous prime is 11120110021. The next prime is 11120110051. The reversal of 11120110033 is 33001102111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11120110033 - 2⁹ = 11120109521 is a prime.

It is a super-2 number, since 2×11120110033² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11120109995 and 11120110022.

It is not an unprimeable number, because it can be changed into a prime (11120110013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6854991 + ... + 6856612.

It is an arithmetic number, because the mean of its divisors is an integer number (2783455612).

Almost surely, 2^11120110033 is an apocalyptic number.

It is an amenable number.

11120110033 is a deficient number, since it is larger than the sum of its proper divisors (13712415).

11120110033 is an equidigital number, since it uses as much as digits as its factorization.

11120110033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13712414.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11120110033 its reverse (33001102111), we get a palindrome (44121212144).

The spelling of 11120110033 in words is "eleven billion, one hundred twenty million, one hundred ten thousand, thirty-three".