Base | Representation |
---|---|
bin | 10100101101100111… |
… | …11001000101011001 |
3 | 1001200222110122002222 |
4 | 22112303321011121 |
5 | 140233222321103 |
6 | 5035234433425 |
7 | 542365314242 |
oct | 122663710531 |
9 | 31628418088 |
10 | 11120120153 |
11 | 479702194a |
12 | 21a4132875 |
13 | 1082a9416c |
14 | 776c1bcc9 |
15 | 4513ba638 |
hex | 296cf9159 |
11120120153 has 4 divisors (see below), whose sum is σ = 11120735460. Its totient is φ = 11119504848.
The previous prime is 11120120107. The next prime is 11120120183. The reversal of 11120120153 is 35102102111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35102102111 = 1583 ⋅22174417.
It can be written as a sum of positive squares in 2 ways, for example, as 272481049 + 10847639104 = 16507^2 + 104152^2 .
It is a cyclic number.
It is not a de Polignac number, because 11120120153 - 212 = 11120116057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11120120183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279698 + ... + 316971.
It is an arithmetic number, because the mean of its divisors is an integer number (2780183865).
Almost surely, 211120120153 is an apocalyptic number.
It is an amenable number.
11120120153 is a deficient number, since it is larger than the sum of its proper divisors (615307).
11120120153 is an equidigital number, since it uses as much as digits as its factorization.
11120120153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 615306.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 11120120153 its reverse (35102102111), we get a palindrome (46222222264).
The spelling of 11120120153 in words is "eleven billion, one hundred twenty million, one hundred twenty thousand, one hundred fifty-three".
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