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1112102001113 = 1719164690943
BaseRepresentation
bin10000001011101110011…
…100011101100111011001
310221022112022010010022012
4100023232130131213121
5121210041103013423
62210520445235305
7143226632016425
oct20135634354731
93838468103265
101112102001113
11399704650604
1215b648862b35
1380b4210438c
143bb7c877b85
151dddd16e078
hex102ee71d9d9

1112102001113 has 4 divisors (see below), whose sum is σ = 1112166709248. Its totient is φ = 1112037292980.

The previous prime is 1112102001089. The next prime is 1112102001163. The reversal of 1112102001113 is 3111002012111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1112102001113 - 210 = 1112102000089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1112102001163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32328281 + ... + 32362662.

It is an arithmetic number, because the mean of its divisors is an integer number (278041677312).

Almost surely, 21112102001113 is an apocalyptic number.

It is an amenable number.

1112102001113 is a deficient number, since it is larger than the sum of its proper divisors (64708135).

1112102001113 is an equidigital number, since it uses as much as digits as its factorization.

1112102001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64708134.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1112102001113 its reverse (3111002012111), we get a palindrome (4223104013224).

The spelling of 1112102001113 in words is "one trillion, one hundred twelve billion, one hundred two million, one thousand, one hundred thirteen".

Divisors: 1 17191 64690943 1112102001113