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1112103113113 = 5918849205307
BaseRepresentation
bin10000001011101110100…
…000101101000110011001
310221022112101012121200101
4100023232200231012121
5121210041344104423
62210520525135401
7143226644330416
oct20135640550631
93838471177611
101112103113113
11399705240013
1215b6490ba561
1380b42403575
143bb7ca8710d
151dddd2dd7ad
hex102ee82d199

1112103113113 has 4 divisors (see below), whose sum is σ = 1130952318480. Its totient is φ = 1093253907748.

The previous prime is 1112103113081. The next prime is 1112103113117. The reversal of 1112103113113 is 3113113012111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1112103113113 - 25 = 1112103113081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1112103113117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9424602595 + ... + 9424602712.

It is an arithmetic number, because the mean of its divisors is an integer number (282738079620).

Almost surely, 21112103113113 is an apocalyptic number.

It is an amenable number.

1112103113113 is a deficient number, since it is larger than the sum of its proper divisors (18849205367).

1112103113113 is an equidigital number, since it uses as much as digits as its factorization.

1112103113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18849205366.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1112103113113 its reverse (3113113012111), we get a palindrome (4225216125224).

The spelling of 1112103113113 in words is "one trillion, one hundred twelve billion, one hundred three million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 59 18849205307 1112103113113