Base | Representation |
---|---|
bin | 10000001011101110100… |
… | …000101101000110011001 |
3 | 10221022112101012121200101 |
4 | 100023232200231012121 |
5 | 121210041344104423 |
6 | 2210520525135401 |
7 | 143226644330416 |
oct | 20135640550631 |
9 | 3838471177611 |
10 | 1112103113113 |
11 | 399705240013 |
12 | 15b6490ba561 |
13 | 80b42403575 |
14 | 3bb7ca8710d |
15 | 1dddd2dd7ad |
hex | 102ee82d199 |
1112103113113 has 4 divisors (see below), whose sum is σ = 1130952318480. Its totient is φ = 1093253907748.
The previous prime is 1112103113081. The next prime is 1112103113117. The reversal of 1112103113113 is 3113113012111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1112103113113 - 25 = 1112103113081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1112103113117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9424602595 + ... + 9424602712.
It is an arithmetic number, because the mean of its divisors is an integer number (282738079620).
Almost surely, 21112103113113 is an apocalyptic number.
It is an amenable number.
1112103113113 is a deficient number, since it is larger than the sum of its proper divisors (18849205367).
1112103113113 is an equidigital number, since it uses as much as digits as its factorization.
1112103113113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18849205366.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 1112103113113 its reverse (3113113012111), we get a palindrome (4225216125224).
The spelling of 1112103113113 in words is "one trillion, one hundred twelve billion, one hundred three million, one hundred thirteen thousand, one hundred thirteen".
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