Base | Representation |
---|---|
bin | 10000001011101111000… |
… | …111001110111001001011 |
3 | 10221022120002012202010101 |
4 | 100023233013032321023 |
5 | 121210101440304003 |
6 | 2210521525430231 |
7 | 143230126224232 |
oct | 20135707167113 |
9 | 3838502182111 |
10 | 1112113213003 |
11 | 39970aa09231 |
12 | 15b65056b377 |
13 | 80b4452b730 |
14 | 3bb80155b19 |
15 | 1ddde13611d |
hex | 102ef1cee4b |
1112113213003 has 4 divisors (see below), whose sum is σ = 1197660383248. Its totient is φ = 1026566042760.
The previous prime is 1112113212989. The next prime is 1112113213021. The reversal of 1112113213003 is 3003123112111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112113213003 - 221 = 1112111115851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1112113213073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42773585103 + ... + 42773585128.
It is an arithmetic number, because the mean of its divisors is an integer number (299415095812).
Almost surely, 21112113213003 is an apocalyptic number.
1112113213003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1112113213003 is a deficient number, since it is larger than the sum of its proper divisors (85547170245).
1112113213003 is an equidigital number, since it uses as much as digits as its factorization.
1112113213003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85547170244.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1112113213003 its reverse (3003123112111), we get a palindrome (4115236325114).
The spelling of 1112113213003 in words is "one trillion, one hundred twelve billion, one hundred thirteen million, two hundred thirteen thousand, three".
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