1112113220131 has 4 divisors (see below), whose sum is σ = 1112804404600. Its totient is φ = 1111422035664.

The previous prime is 1112113220027. The next prime is 1112113220171. The reversal of 1112113220131 is 1310223112111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1112113220131 - 2¹³ = 1112113211939 is a prime.

It is a super-2 number, since 2×1112113220131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112113220099 and 1112113220108.

It is not an unprimeable number, because it can be changed into a prime (1112113220171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345589821 + ... + 345593038.

It is an arithmetic number, because the mean of its divisors is an integer number (278201101150).

Almost surely, 2^{1112113220131} is an apocalyptic number.

1112113220131 is a deficient number, since it is larger than the sum of its proper divisors (691184469).

1112113220131 is an equidigital number, since it uses as much as digits as its factorization.

1112113220131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 691184468.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1112113220131 its reverse (1310223112111), we get a palindrome (2422336332242).

The spelling of 1112113220131 in words is "one trillion, one hundred twelve billion, one hundred thirteen million, two hundred twenty thousand, one hundred thirty-one".