Base | Representation |
---|---|
bin | 10100101101110000… |
… | …00001000001010001 |
3 | 1001201001111120001222 |
4 | 22112320001001101 |
5 | 140234011414413 |
6 | 5035313534425 |
7 | 542410436132 |
oct | 122670010121 |
9 | 31631446058 |
10 | 11121201233 |
11 | 47976a00aa |
12 | 21a4574415 |
13 | 108308225c |
14 | 77701dc89 |
15 | 451530b08 |
hex | 296e01051 |
11121201233 has 4 divisors (see below), whose sum is σ = 11121627120. Its totient is φ = 11120775348.
The previous prime is 11121201193. The next prime is 11121201263. The reversal of 11121201233 is 33210212111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33210212111 = 631 ⋅52631081.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11121201233 is a prime.
It is a super-2 number, since 2×111212012332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11121201263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171023 + ... + 226916.
It is an arithmetic number, because the mean of its divisors is an integer number (2780406780).
Almost surely, 211121201233 is an apocalyptic number.
It is an amenable number.
11121201233 is a deficient number, since it is larger than the sum of its proper divisors (425887).
11121201233 is an equidigital number, since it uses as much as digits as its factorization.
11121201233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425886.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11121201233 its reverse (33210212111), we get a palindrome (44331413344).
The spelling of 11121201233 in words is "eleven billion, one hundred twenty-one million, two hundred one thousand, two hundred thirty-three".
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