1112132320113 has 4 divisors (see below), whose sum is σ = 1482843093488. Its totient is φ = 741421546740.

The previous prime is 1112132320111. The next prime is 1112132320129. The reversal of 1112132320113 is 3110232312111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1112132320113 - 2¹ = 1112132320111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1112132320113.

It is not an unprimeable number, because it can be changed into a prime (1112132320111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185355386683 + ... + 185355386688.

It is an arithmetic number, because the mean of its divisors is an integer number (370710773372).

Almost surely, 2^{1112132320113} is an apocalyptic number.

It is an amenable number.

1112132320113 is a deficient number, since it is larger than the sum of its proper divisors (370710773375).

1112132320113 is an equidigital number, since it uses as much as digits as its factorization.

1112132320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 370710773374.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1112132320113 its reverse (3110232312111), we get a palindrome (4222364632224).

The spelling of 1112132320113 in words is "one trillion, one hundred twelve billion, one hundred thirty-two million, three hundred twenty thousand, one hundred thirteen".