11122041113 has 4 divisors (see below), whose sum is σ = 11128064640. Its totient is φ = 11116017588.

The previous prime is 11122041107. The next prime is 11122041137. The reversal of 11122041113 is 31114022111.

11122041113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11122041113 - 2²² = 11117846809 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11122041091 and 11122041100.

It is not an unprimeable number, because it can be changed into a prime (11122041163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3008993 + ... + 3012686.

It is an arithmetic number, because the mean of its divisors is an integer number (2782016160).

Almost surely, 2^11122041113 is an apocalyptic number.

It is an amenable number.

11122041113 is a deficient number, since it is larger than the sum of its proper divisors (6023527).

11122041113 is an equidigital number, since it uses as much as digits as its factorization.

11122041113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6023526.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11122041113 its reverse (31114022111), we get a palindrome (42236063224).

The spelling of 11122041113 in words is "eleven billion, one hundred twenty-two million, forty-one thousand, one hundred thirteen".