11122101001113 has 4 divisors (see below), whose sum is σ = 14829468001488. Its totient is φ = 7414734000740.

The previous prime is 11122101001031. The next prime is 11122101001163. The reversal of 11122101001113 is 31110010122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11122101001113 - 2⁹ = 11122101000601 is a prime.

It is a super-2 number, since 2×11122101001113² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11122101001092 and 11122101001101.

It is not an unprimeable number, because it can be changed into a prime (11122101001163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1853683500183 + ... + 1853683500188.

It is an arithmetic number, because the mean of its divisors is an integer number (3707367000372).

Almost surely, 2^{11122101001113} is an apocalyptic number.

It is an amenable number.

11122101001113 is a deficient number, since it is larger than the sum of its proper divisors (3707367000375).

11122101001113 is an equidigital number, since it uses as much as digits as its factorization.

11122101001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3707367000374.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 11122101001113 its reverse (31110010122111), we get a palindrome (42232111123224).

The spelling of 11122101001113 in words is "eleven trillion, one hundred twenty-two billion, one hundred one million, one thousand, one hundred thirteen".