Base | Representation |
---|---|
bin | 10000001011110110101… |
… | …111000101011010010001 |
3 | 10221022212222212002200212 |
4 | 100023312233011122101 |
5 | 121210332210203213 |
6 | 2210542334453505 |
7 | 143233241236001 |
oct | 20136657053221 |
9 | 3838788762625 |
10 | 1112241100433 |
11 | 399776117a21 |
12 | 15b687364295 |
13 | 80b64b87778 |
14 | 3bb93126001 |
15 | 1ddea4989a8 |
hex | 102f6bc5691 |
1112241100433 has 8 divisors (see below), whose sum is σ = 1112628840576. Its totient is φ = 1111853433600.
The previous prime is 1112241100357. The next prime is 1112241100483. The reversal of 1112241100433 is 3340011422111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112241100433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1112241100399 and 1112241100408.
It is not an unprimeable number, because it can be changed into a prime (1112241100483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55157873 + ... + 55178033.
It is an arithmetic number, because the mean of its divisors is an integer number (139078605072).
Almost surely, 21112241100433 is an apocalyptic number.
It is an amenable number.
1112241100433 is a deficient number, since it is larger than the sum of its proper divisors (387740143).
1112241100433 is a wasteful number, since it uses less digits than its factorization.
1112241100433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36655.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1112241100433 its reverse (3340011422111), we get a palindrome (4452252522544).
The spelling of 1112241100433 in words is "one trillion, one hundred twelve billion, two hundred forty-one million, one hundred thousand, four hundred thirty-three".
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