111230051113 has 4 divisors (see below), whose sum is σ = 111652979328. Its totient is φ = 110807122900.

The previous prime is 111230051069. The next prime is 111230051131. The reversal of 111230051113 is 311150032111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311150032111 = 73 ⋅4262329207.

It is a cyclic number.

It is not a de Polignac number, because 111230051113 - 2¹³ = 111230042921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111230051143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211463713 + ... + 211464238.

It is an arithmetic number, because the mean of its divisors is an integer number (27913244832).

Almost surely, 2^111230051113 is an apocalyptic number.

It is an amenable number.

111230051113 is a deficient number, since it is larger than the sum of its proper divisors (422928215).

111230051113 is an equidigital number, since it uses as much as digits as its factorization.

111230051113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 422928214.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 111230051113 its reverse (311150032111), we get a palindrome (422380083224).

The spelling of 111230051113 in words is "one hundred eleven billion, two hundred thirty million, fifty-one thousand, one hundred thirteen".