111230130113 has 4 divisors (see below), whose sum is σ = 111230853588. Its totient is φ = 111229406640.

The previous prime is 111230130079. The next prime is 111230130131. The reversal of 111230130113 is 311031032111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 22754817409 + 88475312704 = 150847^2 + 297448^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111230130113 is a prime.

It is a super-3 number, since 3×111230130113³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111230130091 and 111230130100.

It is not an unprimeable number, because it can be changed into a prime (111230130313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29258 + ... + 472563.

It is an arithmetic number, because the mean of its divisors is an integer number (27807713397).

Almost surely, 2^111230130113 is an apocalyptic number.

It is an amenable number.

111230130113 is a deficient number, since it is larger than the sum of its proper divisors (723475).

111230130113 is an equidigital number, since it uses as much as digits as its factorization.

111230130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 723474.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 111230130113 its reverse (311031032111), we get a palindrome (422261162224).

The spelling of 111230130113 in words is "one hundred eleven billion, two hundred thirty million, one hundred thirty thousand, one hundred thirteen".