Base | Representation |
---|---|
bin | 1010000111011100011101… |
… | …0011001000011000100011 |
3 | 1110101100102222012212210210 |
4 | 2201313013103020120203 |
5 | 2424214413041313103 |
6 | 35353501520425203 |
7 | 2225416441053141 |
oct | 241670723103043 |
9 | 43340388185723 |
10 | 11123014010403 |
11 | 35a9275483719 |
12 | 12b786aa78203 |
13 | 628b84b89a19 |
14 | 2a64dccd0591 |
15 | 14450606ee03 |
hex | a1dc74c8623 |
11123014010403 has 4 divisors (see below), whose sum is σ = 14830685347208. Its totient is φ = 7415342673600.
The previous prime is 11123014010371. The next prime is 11123014010417. The reversal of 11123014010403 is 30401041032111.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11123014010403 - 25 = 11123014010371 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11123014010403.
It is not an unprimeable number, because it can be changed into a prime (11123014010443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1853835668398 + ... + 1853835668403.
It is an arithmetic number, because the mean of its divisors is an integer number (3707671336802).
Almost surely, 211123014010403 is an apocalyptic number.
11123014010403 is a deficient number, since it is larger than the sum of its proper divisors (3707671336805).
11123014010403 is an equidigital number, since it uses as much as digits as its factorization.
11123014010403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3707671336804.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 11123014010403 its reverse (30401041032111), we get a palindrome (41524055042514).
The spelling of 11123014010403 in words is "eleven trillion, one hundred twenty-three billion, fourteen million, ten thousand, four hundred three".
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