Base | Representation |
---|---|
bin | 110011110010111011… |
… | …0010011101000011011 |
3 | 101122002211121211022101 |
4 | 1213211312103220123 |
5 | 3310244440313201 |
6 | 123033141304231 |
7 | 11015251544350 |
oct | 1474566235033 |
9 | 348084554271 |
10 | 111230401051 |
11 | 43199730690 |
12 | 19682a05077 |
13 | a6483a6a73 |
14 | 5552788627 |
15 | 2d6013ad01 |
hex | 19e5d93a1b |
111230401051 has 16 divisors (see below), whose sum is σ = 142059230208. Its totient is φ = 84559060800.
The previous prime is 111230400997. The next prime is 111230401097. The reversal of 111230401051 is 150104032111.
It is a cyclic number.
It is not a de Polignac number, because 111230401051 - 215 = 111230368283 is a prime.
It is not an unprimeable number, because it can be changed into a prime (111230401351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17613315 + ... + 17619628.
It is an arithmetic number, because the mean of its divisors is an integer number (8878701888).
Almost surely, 2111230401051 is an apocalyptic number.
111230401051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
111230401051 is a deficient number, since it is larger than the sum of its proper divisors (30828829157).
111230401051 is a wasteful number, since it uses less digits than its factorization.
111230401051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35233002.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 111230401051 its reverse (150104032111), we get a palindrome (261334433162).
The spelling of 111230401051 in words is "one hundred eleven billion, two hundred thirty million, four hundred one thousand, fifty-one".
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