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11123220113 = 21152716683
BaseRepresentation
bin10100101101111111…
…01101111010010001
31001201012022010110022
422112333231322101
5140240021020423
65035425113225
7542433545105
oct122677557221
931635263408
1011123220113
1147988499a5
1221a5188815
13108360b165
147773c7905
154517cddc8
hex296fede91

11123220113 has 4 divisors (see below), whose sum is σ = 11175937008. Its totient is φ = 11070503220.

The previous prime is 11123220029. The next prime is 11123220133. The reversal of 11123220113 is 31102232111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11123220113 - 28 = 11123219857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11123220091 and 11123220100.

It is not an unprimeable number, because it can be changed into a prime (11123220133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26358131 + ... + 26358552.

It is an arithmetic number, because the mean of its divisors is an integer number (2793984252).

Almost surely, 211123220113 is an apocalyptic number.

It is an amenable number.

11123220113 is a deficient number, since it is larger than the sum of its proper divisors (52716895).

11123220113 is an equidigital number, since it uses as much as digits as its factorization.

11123220113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52716894.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11123220113 its reverse (31102232111), we get a palindrome (42225452224).

The spelling of 11123220113 in words is "eleven billion, one hundred twenty-three million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 211 52716683 11123220113