1112323314433 has 4 divisors (see below), whose sum is σ = 1112624679088. Its totient is φ = 1112021949780.

The previous prime is 1112323314331. The next prime is 1112323314437. The reversal of 1112323314433 is 3344133232111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112323314433 is a prime.

It is a super-2 number, since 2×1112323314433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112323314395 and 1112323314404.

It is not an unprimeable number, because it can be changed into a prime (1112323314437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150676791 + ... + 150684172.

It is an arithmetic number, because the mean of its divisors is an integer number (278156169772).

Almost surely, 2^{1112323314433} is an apocalyptic number.

It is an amenable number.

1112323314433 is a deficient number, since it is larger than the sum of its proper divisors (301364655).

1112323314433 is an equidigital number, since it uses as much as digits as its factorization.

1112323314433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 301364654.

The product of its digits is 15552, while the sum is 31.

Adding to 1112323314433 its reverse (3344133232111), we get a palindrome (4456456546544).

The spelling of 1112323314433 in words is "one trillion, one hundred twelve billion, three hundred twenty-three million, three hundred fourteen thousand, four hundred thirty-three".