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11123314131 = 35582966413
BaseRepresentation
bin10100101110000000…
…00100110111010011
31001201012110220102110
422113000010313103
5140240032023011
65035431120403
7542434416156
oct122700046723
931635426373
1011123314131
1147989035a6
1221a5213103
131083641ba7
1477740dc9d
154517ebba6
hex297004dd3

11123314131 has 8 divisors (see below), whose sum is σ = 14831574480. Its totient is φ = 7415298272.

The previous prime is 11123314127. The next prime is 11123314141. The reversal of 11123314131 is 13141332111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11123314131 - 22 = 11123314127 is a prime.

It is a super-2 number, since 2×111233141312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11123314098 and 11123314107.

It is not an unprimeable number, because it can be changed into a prime (11123314121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 134281 + ... + 200693.

It is an arithmetic number, because the mean of its divisors is an integer number (1853946810).

Almost surely, 211123314131 is an apocalyptic number.

11123314131 is a deficient number, since it is larger than the sum of its proper divisors (3708260349).

11123314131 is an equidigital number, since it uses as much as digits as its factorization.

11123314131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122245.

The product of its digits is 216, while the sum is 21.

Adding to 11123314131 its reverse (13141332111), we get a palindrome (24264646242).

The spelling of 11123314131 in words is "eleven billion, one hundred twenty-three million, three hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 3 55829 66413 167487 199239 3707771377 11123314131