11130004110433 has 4 divisors (see below), whose sum is σ = 11986158272788. Its totient is φ = 10273849948080.

The previous prime is 11130004110419. The next prime is 11130004110493. The reversal of 11130004110433 is 33401140003111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1114981829329 + 10015022281104 = 1055927^2 + 3164652^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11130004110433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130004110493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428077081158 + ... + 428077081183.

It is an arithmetic number, because the mean of its divisors is an integer number (2996539568197).

Almost surely, 2^{11130004110433} is an apocalyptic number.

11130004110433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11130004110433 is a deficient number, since it is larger than the sum of its proper divisors (856154162355).

11130004110433 is an equidigital number, since it uses as much as digits as its factorization.

11130004110433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 856154162354.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11130004110433 its reverse (33401140003111), we get a palindrome (44531144113544).

The spelling of 11130004110433 in words is "eleven trillion, one hundred thirty billion, four million, one hundred ten thousand, four hundred thirty-three".