11130020113 has 8 divisors (see below), whose sum is σ = 11519965800. Its totient is φ = 10740484608.

The previous prime is 11130020017. The next prime is 11130020129. The reversal of 11130020113 is 31102003111.

It can be written as a sum of positive squares in 4 ways, for example, as 4177295424 + 6952724689 = 64632^2 + 83383^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11130020113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11130020093 and 11130020102.

It is not an unprimeable number, because it can be changed into a prime (11130020813) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46806 + ... + 156367.

It is an arithmetic number, because the mean of its divisors is an integer number (1439995725).

Almost surely, 2^11130020113 is an apocalyptic number.

It is an amenable number.

11130020113 is a deficient number, since it is larger than the sum of its proper divisors (389945687).

11130020113 is a wasteful number, since it uses less digits than its factorization.

11130020113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 205091.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11130020113 its reverse (31102003111), we get a palindrome (42232023224).

The spelling of 11130020113 in words is "eleven billion, one hundred thirty million, twenty thousand, one hundred thirteen".