11130210023131 has 4 divisors (see below), whose sum is σ = 11130225287472. Its totient is φ = 11130194758792.

The previous prime is 11130210023117. The next prime is 11130210023143. The reversal of 11130210023131 is 13132001203111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11130210023131 - 2⁵ = 11130210023099 is a prime.

It is a super-2 number, since 2×11130210023131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11130210023099 and 11130210023108.

It is not an unprimeable number, because it can be changed into a prime (11130210023111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6480496 + ... + 8016061.

It is an arithmetic number, because the mean of its divisors is an integer number (2782556321868).

Almost surely, 2^{11130210023131} is an apocalyptic number.

11130210023131 is a deficient number, since it is larger than the sum of its proper divisors (15264341).

11130210023131 is an equidigital number, since it uses as much as digits as its factorization.

11130210023131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15264340.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11130210023131 its reverse (13132001203111), we get a palindrome (24262211226242).

The spelling of 11130210023131 in words is "eleven trillion, one hundred thirty billion, two hundred ten million, twenty-three thousand, one hundred thirty-one".