Base | Representation |
---|---|
bin | 110011110101000011… |
… | …1111100100101100001 |
3 | 101122021211121020120110 |
4 | 1213222013330211201 |
5 | 3310421321242423 |
6 | 123044223001533 |
7 | 11020112346552 |
oct | 1475207744541 |
9 | 348254536513 |
10 | 111302134113 |
11 | 43226175805 |
12 | 196a2a392a9 |
13 | a65a201371 |
14 | 555c0dc329 |
15 | 2d665aa193 |
hex | 19ea1fc961 |
111302134113 has 8 divisors (see below), whose sum is σ = 153190034176. Its totient is φ = 71807828400.
The previous prime is 111302134087. The next prime is 111302134123. The reversal of 111302134113 is 311431203111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 111302134113 - 25 = 111302134081 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 111302134113.
It is not an unprimeable number, because it can be changed into a prime (111302134123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 598398478 + ... + 598398663.
It is an arithmetic number, because the mean of its divisors is an integer number (19148754272).
Almost surely, 2111302134113 is an apocalyptic number.
It is an amenable number.
111302134113 is a deficient number, since it is larger than the sum of its proper divisors (41887900063).
111302134113 is a wasteful number, since it uses less digits than its factorization.
111302134113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1196797175.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 111302134113 its reverse (311431203111), we get a palindrome (422733337224).
The spelling of 111302134113 in words is "one hundred eleven billion, three hundred two million, one hundred thirty-four thousand, one hundred thirteen".
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