1113024113 has 4 divisors (see below), whose sum is σ = 1115059440. Its totient is φ = 1110988788.

The previous prime is 1113024103. The next prime is 1113024131. The reversal of 1113024113 is 3114203111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113024113 - 2⁴ = 1113024097 is a prime.

It is a super-2 number, since 2×1113024113² = 2477645352238873538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113024091 and 1113024100.

It is not an unprimeable number, because it can be changed into a prime (1113024103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1016843 + ... + 1017936.

It is an arithmetic number, because the mean of its divisors is an integer number (278764860).

Almost surely, 2^1113024113 is an apocalyptic number.

It is an amenable number.

1113024113 is a deficient number, since it is larger than the sum of its proper divisors (2035327).

1113024113 is an equidigital number, since it uses as much as digits as its factorization.

1113024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2035326.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1113024113 is about 33362.0160212179. The cubic root of 1113024113 is about 1036.3382420079.

Adding to 1113024113 its reverse (3114203111), we get a palindrome (4227227224).

The spelling of 1113024113 in words is "one billion, one hundred thirteen million, twenty-four thousand, one hundred thirteen".