11130313112113 has 4 divisors (see below), whose sum is σ = 11986491043828. Its totient is φ = 10274135180400.

The previous prime is 11130313112077. The next prime is 11130313112117. The reversal of 11130313112113 is 31121131303111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5883501401649 + 5246811710464 = 2425593^2 + 2290592^2 .

It is not a de Polignac number, because 11130313112113 - 2¹⁷ = 11130312981041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130313112117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428088965838 + ... + 428088965863.

It is an arithmetic number, because the mean of its divisors is an integer number (2996622760957).

Almost surely, 2^{11130313112113} is an apocalyptic number.

11130313112113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11130313112113 is a deficient number, since it is larger than the sum of its proper divisors (856177931715).

11130313112113 is an equidigital number, since it uses as much as digits as its factorization.

11130313112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 856177931714.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 11130313112113 its reverse (31121131303111), we get a palindrome (42251444415224).

The spelling of 11130313112113 in words is "eleven trillion, one hundred thirty billion, three hundred thirteen million, one hundred twelve thousand, one hundred thirteen".