1113102033131 has 4 divisors (see below), whose sum is σ = 1214293127064. Its totient is φ = 1011910939200.

The previous prime is 1113102033037. The next prime is 1113102033151. The reversal of 1113102033131 is 1313302013111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113102033131 - 2³⁰ = 1112028291307 is a prime.

It is a super-2 number, since 2×1113102033131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113102033151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50595546950 + ... + 50595546971.

It is an arithmetic number, because the mean of its divisors is an integer number (303573281766).

Almost surely, 2^{1113102033131} is an apocalyptic number.

1113102033131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1113102033131 is a deficient number, since it is larger than the sum of its proper divisors (101191093933).

1113102033131 is a wasteful number, since it uses less digits than its factorization.

1113102033131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101191093932.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1113102033131 its reverse (1313302013111), we get a palindrome (2426404046242).

The spelling of 1113102033131 in words is "one trillion, one hundred thirteen billion, one hundred two million, thirty-three thousand, one hundred thirty-one".