Base | Representation |
---|---|
bin | 10000001100101010100… |
… | …101111000001001010001 |
3 | 10221102010121220202112100 |
4 | 100030222211320021101 |
5 | 121214122420231113 |
6 | 2211204533551013 |
7 | 143263634153550 |
oct | 20145245701121 |
9 | 3842117822470 |
10 | 1113111102033 |
11 | 39a082220007 |
12 | 15b88a7a5469 |
13 | 80c731a9b08 |
14 | 3bc368b3d97 |
15 | 1de4ba4bd73 |
hex | 1032a978251 |
1113111102033 has 144 divisors (see below), whose sum is σ = 2099517428736. Its totient is φ = 554139463680.
The previous prime is 1113111102023. The next prime is 1113111102049. The reversal of 1113111102033 is 3302011113111.
It is not a de Polignac number, because 1113111102033 - 221 = 1113109004881 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113111101997 and 1113111102015.
It is not an unprimeable number, because it can be changed into a prime (1113111102023) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 17531641 + ... + 17595017.
It is an arithmetic number, because the mean of its divisors is an integer number (14579982144).
Almost surely, 21113111102033 is an apocalyptic number.
It is an amenable number.
1113111102033 is a deficient number, since it is larger than the sum of its proper divisors (986406326703).
1113111102033 is a wasteful number, since it uses less digits than its factorization.
1113111102033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63484 (or 63458 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 1113111102033 its reverse (3302011113111), we get a palindrome (4415122215144).
The spelling of 1113111102033 in words is "one trillion, one hundred thirteen billion, one hundred eleven million, one hundred two thousand, thirty-three".
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