11131113120001 has 4 divisors (see below), whose sum is σ = 12721272137152. Its totient is φ = 9540954102852.

The previous prime is 11131113119999. The next prime is 11131113120007. The reversal of 11131113120001 is 10002131113111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11131113120001 - 2¹ = 11131113119999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11131113120007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795079508565 + ... + 795079508578.

It is an arithmetic number, because the mean of its divisors is an integer number (3180318034288).

Almost surely, 2^{11131113120001} is an apocalyptic number.

It is an amenable number.

11131113120001 is a deficient number, since it is larger than the sum of its proper divisors (1590159017151).

11131113120001 is an equidigital number, since it uses as much as digits as its factorization.

11131113120001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1590159017150.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 11131113120001 its reverse (10002131113111), we get a palindrome (21133244233112).

The spelling of 11131113120001 in words is "eleven trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred twenty thousand, one".