111312030113 has 4 divisors (see below), whose sum is σ = 111563299248. Its totient is φ = 111060760980.

The previous prime is 111312030091. The next prime is 111312030127. The reversal of 111312030113 is 311030213111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111312030113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 111312030091 and 111312030100.

It is not an unprimeable number, because it can be changed into a prime (111312030133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125633903 + ... + 125634788.

It is an arithmetic number, because the mean of its divisors is an integer number (27890824812).

Almost surely, 2^111312030113 is an apocalyptic number.

It is an amenable number.

111312030113 is a deficient number, since it is larger than the sum of its proper divisors (251269135).

111312030113 is an equidigital number, since it uses as much as digits as its factorization.

111312030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251269134.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 111312030113 its reverse (311030213111), we get a palindrome (422342243224).

The spelling of 111312030113 in words is "one hundred eleven billion, three hundred twelve million, thirty thousand, one hundred thirteen".