1113122564403 has 4 divisors (see below), whose sum is σ = 1484163419208. Its totient is φ = 742081709600.

The previous prime is 1113122564383. The next prime is 1113122564443. The reversal of 1113122564403 is 3044652213111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113122564403 - 2¹⁴ = 1113122548019 is a prime.

It is a super-2 number, since 2×1113122564403² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1113122564443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185520427398 + ... + 185520427403.

It is an arithmetic number, because the mean of its divisors is an integer number (371040854802).

Almost surely, 2^{1113122564403} is an apocalyptic number.

1113122564403 is a deficient number, since it is larger than the sum of its proper divisors (371040854805).

1113122564403 is an equidigital number, since it uses as much as digits as its factorization.

1113122564403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371040854804.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 1113122564403 its reverse (3044652213111), we get a palindrome (4157774777514).

The spelling of 1113122564403 in words is "one trillion, one hundred thirteen billion, one hundred twenty-two million, five hundred sixty-four thousand, four hundred three".