1113141300001 has 4 divisors (see below), whose sum is σ = 1149049083904. Its totient is φ = 1077233516100.

The previous prime is 1113141299999. The next prime is 1113141300107. The reversal of 1113141300001 is 1000031413111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113141300001 - 2¹ = 1113141299999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113141301001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17953891905 + ... + 17953891966.

It is an arithmetic number, because the mean of its divisors is an integer number (287262270976).

Almost surely, 2^{1113141300001} is an apocalyptic number.

It is an amenable number.

1113141300001 is a deficient number, since it is larger than the sum of its proper divisors (35907783903).

1113141300001 is an equidigital number, since it uses as much as digits as its factorization.

1113141300001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35907783902.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1113141300001 its reverse (1000031413111), we get a palindrome (2113172713112).

The spelling of 1113141300001 in words is "one trillion, one hundred thirteen billion, one hundred forty-one million, three hundred thousand, one".