Base | Representation |
---|---|
bin | 10000001100101110010… |
… | …111000100100000111001 |
3 | 10221102022000220001011201 |
4 | 100030232113010200321 |
5 | 121214240112020101 |
6 | 2211215113054201 |
7 | 143265332452111 |
oct | 20145627044071 |
9 | 3842260801151 |
10 | 1113174329401 |
11 | 39a104985732 |
12 | 15b8a79b7361 |
13 | 80c83316a64 |
14 | 3bc41052041 |
15 | 1de5238ae01 |
hex | 1032e5c4839 |
1113174329401 has 4 divisors (see below), whose sum is σ = 1161573213312. Its totient is φ = 1064775445492.
The previous prime is 1113174329389. The next prime is 1113174329411. The reversal of 1113174329401 is 1049234713111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1113174329401 - 225 = 1113140774969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1113174329411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24199441921 + ... + 24199441966.
It is an arithmetic number, because the mean of its divisors is an integer number (290393303328).
Almost surely, 21113174329401 is an apocalyptic number.
It is an amenable number.
1113174329401 is a deficient number, since it is larger than the sum of its proper divisors (48398883911).
1113174329401 is an equidigital number, since it uses as much as digits as its factorization.
1113174329401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48398883910.
The product of its (nonzero) digits is 18144, while the sum is 37.
The spelling of 1113174329401 in words is "one trillion, one hundred thirteen billion, one hundred seventy-four million, three hundred twenty-nine thousand, four hundred one".
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